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  1. Home > Articles & Issues >
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  3. Crucial abelian k-po ...
Article

Crucial abelian k-power-free words

Amy Glen (1), Bjarni V. Halldorsson ORCID (2), Sergey Kitaev ORCID (3)
(1) Department of Mathematics and Statistics [Perth]
(2) Reykjavík University
(3) The Mathematics Institute, Reyjavik University
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Imported on
March 26, 2015
Published on
January 1, 2010
Last modified on
March 31, 2025
Volume 12
vol. 12:5
Combinatorics
DOI
10.46298/dmtcs.513
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https://about.hal.science/hal-authorisation-v1
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Crucial abelian k-power-free words

Amy Glen (1), Bjarni V. Halldorsson ORCID (2), Sergey Kitaev ORCID (3)
(1) Department of Mathematics and Statistics [Perth]
(2) Reykjavík University
(3) The Mathematics Institute, Reyjavik University
Abstract
In 1961, Erdos asked whether or not there exist words of arbitrary length over a fixed finite alphabet that avoid patterns of the form XX' where X' is a permutation of X (called abelian squares). This problem has since been solved in the affirmative in a series of papers from 1968 to 1992. Much less is known in the case of abelian k-th powers, i.e., words of the form X1X2 ... X-k where X-i is a permutation of X-1 for 2 <= i <= k. In this paper, we consider crucial words for abelian k-th powers, i. e., finite words that avoid abelian k-th powers, but which cannot be extended to the right by any letter of their own alphabets without creating an abelian k-th power. More specifically, we consider the problem of determining the minimal length of a crucial word avoiding abelian k-th powers. This problem has already been solved for abelian squares by Evdokimov and Kitaev (2004), who showed that a minimal crucial word over an n-letter alphabet A(n) = \1, 2, ..., n\ avoiding abelian squares has length 4n - 7 for n >= 3. Extending this result, we prove that a minimal crucial word over A(n) avoiding abelian cubes has length 9n - 13 for n >= 5, and it has length 2, 5, 11, and 20 for n = 1, 2, 3, and 4, respectively. Moreover, for n >= 4 and k >= 2, we give a construction of length k(2) (n - 1) - k - 1 of a crucial word over A(n) avoiding abelian k-th powers. This construction gives the minimal length for k = 2 and k = 3. For k >= 4 and n >= 5, we provide a lower bound for the length of crucial words over A(n) avoiding abelian k-th powers.
Keywords
  • [INFO.INFO-DM]Computer Science [cs]/Discrete Mathematics [cs.DM]
  • pattern avoidance
  • abelian square-free word
  • abelian cube-free word
  • abelian power
  • crucial word
  • Zimin word
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